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Q. KF has NaCl structure. The edge length of its unit cell has been found to be 537.6 pm. The distance between $K^{+}$ and $F^{-}$ in KF is

NTA AbhyasNTA Abhyas 2022

Solution:

For Nacl type crystals
$a=2\left(\left(\text{r}\right)_{\text{cation}} \text{+} \, \left(\text{r}\right)_{\text{anion}}\right)$
$\Rightarrow \, \text{r}_{\text{cation}}\text{+} \, \, \text{r}_{\text{anion}}=\frac{a}{2}=\frac{537}{2}=268.5 \, \text{pm}\text{.}$