The pressure exerted by the gas,
$p = \frac{1}{3} \, p \overline{c^2} $
$= \frac{ 1 m}{ 3 \, V} \overline{c^2}$
$= \frac{2}{3} \bigg( \frac{1}{2} m \overline{c^2} \bigg) $
$ ( \therefore \frac{1}{2} m \overline{c^2} = \frac{E}{V} = $ energy per unit volume, V = 1)
p= $ \frac{2}{3} $ E