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  4. KBr contains 32.9 % potassium by mass. If 6.40g of Br2 is made to react with 3.60 g of potassium the actual mass of potassium which reacted with Br2 is

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Q. KBr contains 32.9 % potassium by mass. If 6.40g of $Br_2$ is made to react with 3.60 g of potassium the actual mass of potassium which reacted with $Br_2$ is

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Solution:

$\%$ of bromine in $KBr=100-32.9=67.1\,\%$
$67.1\,g$ of bromine react with potassium $=32.9\,g$
$6.40\,g$ of bromine react with potassium
$=\frac{\left(32.9\, g\right)\times\left(6.40\, g\right)}{\left(67.1 g\right)}$
$=3.138\,g$
$=3.14\,g$