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Chemistry
K text sp of Mg ( OH )2 is 4.0 × 10-6. At what minimum pH, Mg 2+ ions starts precipitating 0.01 MgCl
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Q. $K_{\text {sp }}$ of $Mg ( OH )_2$ is $4.0 \times 10^{-6}$. At what minimum $pH$, $Mg ^{2+}$ ions starts precipitating $0.01\, MgCl$
NEET
NEET 2022
Equilibrium
A
$2+\log 2$
12%
B
$2-\log 2$
32%
C
$12+\log 2$
26%
D
$12-\log 2$
30%
Solution:
Precipitation starts when $Q_{ sp }=K_{ sp }$ :
$ K_{ sp }=\left[ Ca ^{2+}\right]\left[ \overset{\Theta}{O}H ^2\right]^2$
$\therefore[\overset{\Theta}{ OH }]=\left(\frac{4 \times 10^{-6}}{0.01}\right)^{1 / 2}=2 \times 10^{-2} $
$ pOH =-\log 2+2$
$ pH = i 4-[-\log 2+2]=12+\log 2$