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Chemistry
Ksp of CaSO4⋅5H2O is 9 × 10-6, find the volume for 1 g of CaSO4 (M.wt. = 136).
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Q. $K_{sp}$ of $CaSO_4\cdot5H_2O$ is $9 \times 10^{-6}$, find the volume for $1 \,g$ of $CaSO_4$ (M.wt. = 136).
AIIMS
AIIMS 2011
Equilibrium
A
2.45 litre
59%
B
5.1 litre
8%
C
4.52 litre
23%
D
3.2 litre
10%
Solution:
$CaSO_{4} (s) \rightleftharpoons \underset{S}{Ca^{2+}}(aq) +\underset{S}{SO^{2-}_{4}}(aq)$
$K_{s p}=S^{2}=9 \times 10^{-6} $
$S=3 \times 10^{-3} \,mol \,L ^{-1} $
Solubility in $g \, litre ^{-1}$ molecular mass $\times S$
$=136 \times 3 \times 10^{-3}=408 \times 10^{-3} g \,L ^{-1}$
$408 \times 10^{-3} \,g$ of $CaSO _{4}$ present in 1 litre
$1 \,g$ of $CaSO _{4}$ present is $\frac{1}{408 \times 10^{-3}}=2.45$ litre