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Chemistry
K2HgI4 is 40 % ionised in aqueous solution. The value of its van't Hoff factor (i) is :
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Q. $K_2HgI_4$ is $40\%$ ionised in aqueous solution. The value of its van't Hoff factor (i) is :
JEE Main
JEE Main 2019
Solutions
A
1.8
60%
B
2.2
19%
C
2.0
11%
D
1.6
10%
Solution:
For $K_2[HgI_4]$
$i = 1+ 0.4 (3-1)$
$= 1.8$