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Chemistry
K 2 Cr 2 O 7 paper acidified with dilute H 2 SO 4 turns green when exposed to
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Q. $K _2 Cr _2 O _7$ paper acidified with dilute $H _2 SO _4$ turns green when exposed to
JEE Main
JEE Main 2023
A
Hydrogen sulphide
0%
B
Sulphur dioxide
75%
C
Carbon dioxide
12%
D
Sulphur trioxide
12%
Solution:
$3 SO _2+ Cr _2 O _7^{2-}+2 H ^{+} \rightarrow 3 SO _4^{2-}+\underset{\text{green}}{2 Cr ^{+3}}+ H _2 O$