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Q. Joule second is the unit of :

BVP MedicalBVP Medical 2003

Solution:

Angular momentum $ =m\upsilon r $ $ \text{=kilogram }\!\!\times\!\!\text{ }\frac{\text{metre}}{\text{second}}\text{ }\!\!\times\!\!\text{ metre} $ $ \text{=kilogram }\!\!\times\!\!\text{ }\frac{{{\text{(metre)}}^{\text{2}}}\text{ }\!\!\times\!\!\text{ second}}{\text{second }\!\!\times\!\!\text{ second}} $ $ =\left( kg\times \frac{metre}{{{\sec }^{2}}} \right)\times \sec $ $ =joule\times \sec $