1. Tardigrade
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  4. It takes 10 minutes to cool a liquid from 61° C to 59° C. If room temperature is 30° C then find the time taken in cooling from 51° C to 49° C.

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Q. It takes $10$ minutes to cool a liquid from $61^{\circ} C$ to $59^{\circ} C$. If room temperature is $30^{\circ} C$ then find the time taken in cooling from $51^{\circ} C$ to $49^{\circ} C$.

Solution:

In first case $\frac{61-59}{10}=K\left[\frac{61+59}{2}-30\right]$ (i)
In second case $\frac{51-49}{t}=K\left[\frac{51+49}{2}-30\right]$ (ii)
By solving $t=15 \,\min$.