Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. It is well known that a raindrop falls under the influence of the downward gravitational force and opposing resistive force. The latter is known to be proportional to the speed of the drop. Consider a drop of mass $1 \,gm$ falling from a height of $1 \,km$. If it hits the ground with a speed of $50\, ms ^{-1} .$ The work done by the resistive force is

Work, Energy and Power

Solution:

$W_{r}=\Delta K+\Delta U=\frac{1}{2} m v^{2}-m g h$
$=\left(\frac{1}{2} \times 10^{-3} \times 50^{2}\right)-\left(10^{-3} \times 10 \times 10^{3}\right)$
$=1.25-10=-8.75 J$