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Q. It is known that atoms contain protons, neutrons and electrons. If the mass of neutron is assumed to be half of its Qriginal value whereas that of electron is assumed to be twice of this original value. The atomic mass of $_{6} C ^{12}$ will be-

Structure of Atom

Solution:

$A=p+n, A=Z+n$

$A=12, Z=6$

$n=12-6, n=6$

$=\frac{9}{12} \times 100=75 \%$

$=100-75=25 \%$ less mass