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Q. It is known that atoms contain protons, neutrons and electrons. If the mass of neutron is assumed to be half of its original value whereas that of electron is assumed to be twice of this original value. The atomic mass of $_{6}C^{12}$ will be

Structure of Atom

Solution:

A = P + n
A = 12
n = 12-6
A = Z+n
Z = 6
n = 6
$= \frac{9}{12} \times100=75\% =100-15$
$=25\%$ less mass