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Q. It is found that all electromagnetic signals sent from $A$ towards $B$ reach point $C$ . The speed of electromagnetic signals in glass cannot be

Question

NTA AbhyasNTA Abhyas 2020Ray Optics and Optical Instruments

Solution:

Solution
There TIR at B,
$i>i_{C}$
$\therefore \quad 45^{\circ}>\sin ^{-1}\left(\frac{1}{\mu}\right)$
$\therefore \quad 45^{\circ}>\sin ^{-1}\left(\frac{v_g}{c}\right)$
$\therefore \, sin 45^\circ > \, \frac{v_{g}}{C}$
$\therefore \, v_{g} < c\times sin 45^\circ $
$\therefore \, \, v_{g} < 3\times 10^{8}\times \frac{1}{\sqrt{2} \, }$
$\therefore \, \, v_{g} < 2.14\times 10^{8} \, m \, s^{- 1}$