1. Tardigrade
  2. Question
  3. Chemistry
  4. It is an experiment fact that Cs 2[ CuCl 4] is orange coloured but ( NH 4)2[ CuCl 4] is yellow. It is further known that total paramagnetic moment of a unpaired electron is due to spin as well as due to nature of orbital, 'd' orbital contributing more than 's' or ' p '. Thus the total paramagnetic moment of orange compound is found to be more than that of yellow compound. Then which of the following is correct :

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Q. It is an experiment fact that $Cs _{2}\left[ CuCl _{4}\right]$ is orange coloured but $\left( NH _{4}\right)_{2}\left[ CuCl _{4}\right]$ is yellow. It is further known that total paramagnetic moment of a unpaired electron is due to spin as well as due to nature of orbital, 'd' orbital contributing more than 's' or ' $p$ '. Thus the total paramagnetic moment of orange compound is found to be more than that of yellow compound. Then which of the following is correct :

Coordination Compounds

Solution:

$Cs _{2}\left[ CuCl _{4}\right]$ (orange) is tetrahedral because in $Cu ( II )$ the unpaired electron is in $3 d$. But $\left( NH _{4}\right)_{2}\left[ CuCl _{4}\right]$ yellow is square planar because the unpaired electron is not in $3 d$ rather in some promoted state 's' or ' $p$ '.