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Q. Isopropyl alcohol on oxidation forms

Aldehydes Ketones and Carboxylic Acids

Solution:

Isopropyl alcohol forms acetone on oxidation.
The reaction is as follows:
$CH _{3} CH ( OH ) CH _{3} \xrightarrow[{H^+}]{{[O]}} CH _{3} COCH _{3}$