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  4. Ionization potential and electron affinity of fluorine are 17.42 and 3.45 eV atom-1 respectively. Electronegativity of fluorine will be approximately

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Q. Ionization potential and electron affinity of fluorine are 17.42 and 3.45 eV $atom^{-1}$ respectively. Electronegativity of fluorine will be approximately

Classification of Elements and Periodicity in Properties

Solution:

Electronegativity$=0.374 \frac{\left[IE+EA\right]}{2}+0.17$
$=0.374 \frac{\left[17.42+3.45\right]}{2}+0.17=4.07 \approx4$