Thank you for reporting, we will resolve it shortly
Q.
Ionic radii are
Jharkhand CECEJharkhand CECE 2008
Solution:
Ionic radii $ \propto \frac{1}{{{Z}_{eff}}} $ $ {{Z}_{eff}}= $ Effective nuclear charge This $ {{Z}_{eff}} $ is calculated as follows: $ {{Z}_{eff}}=Z- $ screening constant $ (\sigma ) $ This value of screening constant is based upon the number of electrons in valence shell as well as in penultimate shells.