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  4. Intermediates formed during reaction of || ORCNH2 with Br2 and KOH are

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Q. Intermediates formed during reaction of $_{ \, \, || _{_O}^{}}^{RCNH_2}$ with $Br_2$ and KOH are

AIPMTAIPMT 2001Amines

Solution:

The reaction, $ \, \, RCONH_2 + Br_2 + KOH \longrightarrow RNH_2$ is known as Hofmann bromamide reaction. The mechanism of this reaction is given as : (i) $RCONH_2 + Br_2 \longrightarrow RCONHBr + HBr$ (ii) $RCONHBr \xrightarrow {OH^-} R - CO \ddot{N}Br + H_2O$

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