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  4. Intensity of gravitational field due to a uniform rod of mass M and length L at a point P as shown in figure is

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Q. Intensity of gravitational field due to a uniform rod of mass M and length L at a point P as shown in figure isPhysics Question Image

Solution:

$dl = \frac {Gdm}{x^2}$
$\int dl = G\int\frac{M}{L}\frac{dx}{x^{2}}$
$\Rightarrow I = \frac{GM}{L}\int^{2L}_{L}\times^{-2dx}=\frac{GM}{L}\times\frac{1}{2L}=\frac{GM}{2L^{2}}$

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