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Q. Intensity level of sound whose intensity is $10 ^{-8}$ $wm ^{-2}$ is

KCETKCET 2012Waves

Solution:

Intensity level of sound $= 10 \,log\,\frac{I}{I_{0}}\,dB $
$= 10\, log \left(\frac{10^{-8}}{10^{-12}}\right) dB = 40 \, dB$
$\left(\because \,I_{0} = 10^{-12} \,W/m^{2}\right)$