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Q. $ \int{\sin 2x\,d}(\tan x) $ is equal to

JamiaJamia 2011

Solution:

$ I=\int{\sin 2x}\,d(\tan x)=\int{\sin 2x.{{\sec }^{2}}x}\,dx $ $ =2\int{\tan x\,dx}=2\log |\sec x|+C $