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Mathematics
∫777x ⋅77x ⋅ 7x dx =
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Q. $\int7^{7^{7^x}} \cdot7^{7^x} \cdot 7^{x} dx =$
Integrals
A
$\frac{7^{77x}}{\left(log\, 7\right)^{3}} +c$
B
$\frac{7^{77x}}{\left(log\, 7\right)^{2}} +c$
C
$7^{77x}\cdot\left(log \,7\right)^{3} +c$
D
$7^{7^{7^x}}$
Solution:
Correct answer is (a) $\frac{7^{77x}}{\left(log\, 7\right)^{3}} +c$