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Q. Integral curve satisfying $y^{\prime}=\frac{x^2+y^2}{x^2-y^2}, y(1) =2$, has the slope of the curve at the point $(1,2)$, is equal to

Differential Equations

Solution:

$y^{\prime}=\frac{x^2+y^2}{x^2-y^2}$
$y_{(1,2)}^{\prime}=\frac{1+4}{1-4}=\frac{-5}{3}$