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Q. Initially two gas samples $1$ and $2$ are at the same condition. The volume of the two are halved, one isothermally and the other adiabatically. What is the relation between the final pressure $P_1$ and $ P_2$ ?

BITSATBITSAT 2006

Solution:

For isothermal process
$PV = K$ (constant)
$P =\frac{ K }{ V } \ldots(1)$
$=\frac{ K }{ V / 2}=2 K$
For adiabatic process
$PV ^{\gamma}= K$ (constant)
$\therefore P =\frac{ K }{ V ^{\gamma}} \ldots . .(2)$
$=\frac{ K }{( V / 2)^{\gamma}}- K \left(2^{\gamma}\right)$
From Eqs. (1) and (2), we have
$P _{2} > P _{1}$