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Q. Initially system is in equilibrium. Time period of SHM of block in vertical direction is :
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
Net vertical force $=kx+\frac{k x}{\sqrt{2}}cos45\times 2=2kx=ma$
$a=\frac{2 k}{m}x$
$\Rightarrow \omega =\sqrt{\frac{2 k}{m}}$
$\tau=2\pi \sqrt{\frac{m}{2 k}}$