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  3. Chemistry
  4. Initially 3 moles of ' A ' was taken in a text1 textL container. The approx. moles of A left in the container when the following equilibrium established is x× 10- 6 .The value of ' x ' is. 3A leftharpoons B;KC=8× 1015

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Q. Initially 3 moles of ' $A$ ' was taken in a $\text{1} \, \text{L}$ container. The approx. moles of A left in the container when the following equilibrium established is $x\times 10^{- 6}$ .The value of ' $x$ ' is.

$3A \rightleftharpoons B;K_{C}=8\times 10^{15}$

NTA AbhyasNTA Abhyas 2020Equilibrium

Solution:

Solution

Now,

$\frac {1 - x}{(3 x ^{3}}=8\times 10^{15}$

$3x=5\times 10^{- 6}$