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Q. Initially, 0.8 mol of $PCl_{5}$ and 0.2 mol of $PCl_{3}$ are mixed in a one litre vessel. At equilibrium, 0.4 mol of $PCl_{3}$ is present. The value of $K_{c}$ for the reaction, $PCl_{5}\left(g\right)\rightleftharpoons PCl_{3}\left(g\right)+Cl_{2}\left(g\right),$ would be

NTA AbhyasNTA Abhyas 2020Equilibrium

Solution:

Solution

So $x=0.2$

$K_{c}=\frac{\left[P C l_{3}\right] \left[C l_{2}\right]}{\left[P C l_{5}\right]}=\frac{0.4 \times 0.2}{0.6}$

$=0.13\text{ mol }\text{L}^{- 1}$