Question

Increasing order of oxidation state of metal in
$KMnO_4$, $MnCl_2, MnO_2, Mn(OH)_3$ is :

• A. $Mn ( OH )_{3}< MnCl _{2}< MnO _{2}< KMnO _{4}$
• B. $KMnO _{4}< Mn ( OH )_{2}< MnO _{2}< MnCl _{2}$
• C. $MnCl _{2}< Mn ( OH )_{3}< KMnO _{4}< MnO _{2}$
• D. $MnCl _{2}< Mn ( OH )_{3}< MnO _{2}< KMnO _{4}$

Answer 1

Answer: (D)

$\begin{array}{cc} KMnO _{4} & \text { O.N. of } Mn =+7 \\ MnCl _{2} & \text { O. } N \text {. of } Mn =+2 \\ MnO _{2} & \text { O. } N \text {. of } Mn =+4 \\ Mn ( OH )_{3} & \text { O. } N \text {. of } Mn =+3\end{array}$