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Q. In Young's experiment, the wavelength of red light is $7.8\times 10^{- 8} \, cm$ and that of blue light is $5.2\times 10^{- 8} \, cm$ . Value of n for which $\left(n+1 \right)^{th}$ blue bright fringe coincides with $n^{th}$ red fringe is

NTA AbhyasNTA Abhyas 2022

Solution:

As we know that $n_{1} \, \lambda _{1}=n_{2} \, \lambda _{2}$
$\therefore \frac{n_{2}}{n_{1}}=\frac{\lambda _{1}}{\lambda _{2}}=\frac{7.8 \times 10^{- 8}}{5.2 \times 10^{- 8}}=\frac{3}{2}$
Also $n_{2}-n_{1}=1$
$\therefore n_{1}=2$