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Physics
In Young's experiment, if separate between slits is made half, then fringe width will become:
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Q. In Young's experiment, if separate between slits is made half, then fringe width will become:
Rajasthan PMT
Rajasthan PMT 1999
A
double
B
four times
C
half
D
remains same
Solution:
Fringe width $\beta=\frac{\lambda D}{d}$
$D=$ distance between slits and screen.
$d=$ separation between slits.
$\beta'=\frac{\lambda D}{d / 2}=2\left(\frac{\lambda D}{d}\right)$
fringe width becomes double.