Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In Young's double slit experiment, the slits are 2mm apart and are illuminated by photons of two wavelengths $\lambda_1 = 12000 \mathring A $ and $\lambda_2 = 10000 \mathring A.$ At what minimum distance from the common central bright fringe on the screen 2m from the slit will a bright fringe from one interference pattern coincide with a bright fringe from the other ?

NEETNEET 2013Wave Optics

Solution:

According to question $ n_1 \lambda_1 = n_2 \lambda_2$
So $\frac{n_1}{n_2} = \frac{\lambda_2}{\lambda_1} = \frac{10000}{12000} = \frac{5}{6}$
so minimum $n_1$ and $n_2$ are 5 and 6 respectively
$ X_{min} = \frac{n_1 \lambda_1 D}{d} = \frac{5(12000 \times 10^{-10})(2)}{2 \times 10^{-3}}$
$ = 6 \times 10^{-3} m = 6 mm $