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  4. In Young’s double-slit experiment, the separation between the slits is halved and the distance between the slits and the screen is doubled. The fringe width will

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Q. In Young’s double-slit experiment, the separation between the slits is halved and the distance between the slits and the screen is doubled. The fringe width will

NTA AbhyasNTA Abhyas 2022

Solution:

The fringe width in Young’s double-slit experiment
$\beta =\frac{\lambda D}{d}$
where $\lambda $ is the wavelength of light used
$D$ is the distance between slit and screen.
$d$ is the distance between the slit.
$\therefore \, \beta '=\frac{\lambda \left(\right. 2 D \left.\right)}{\frac{d}{2}}=4\frac{\lambda D}{d}=4\beta $