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  4. In YDSE S1 and S2 has intensity I and 9 I respectively. Find difference in intensity between points which has phase difference of π / 2

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Q. In YDSE $S_{1}$ and $S_{2}$ has intensity $I$ and $9 I$ respectively. Find difference in intensity between points which has phase difference of $\pi / 2$

JIPMERJIPMER 2018Wave Optics

Solution:

Solution For Phase difference $\pi / 2$
$I=I_{1}+I_{2}+2 \sqrt{I_{1} I_{2}} \cos \phi$
$=I+9 I+2 \sqrt{I 9 I} \cos \pi / 2$
$=101$
For Phase difference $\pi$
$|=|+9|-6|=4 \mid$
Difference in intensity $=10I-4I=6I$