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Q.
In which of the following molecules the central atom does not have $sp^3$ hybridization ?
AIPMTAIPMT 2010Chemical Bonding and Molecular Structure
Solution:
When the number of hybrid orbitals, H is 4, the hybridization is $sp_3$. $H=\frac{1}{2}[V+M-C+A]$
where, V = number of valence electrons of central atom M = number of monovalent atoms C = total positive charge A = negative charge [a]$C{{H}_{4}},$
$H=\frac{1}{2}[4+4-0+0]=4,$
thus $s{{p}^{3}}$
hybridization [b] For$S{{F}_{4}},$
$H=\frac{1}{2}[6+4-0+0]=5,$
thus $s{{p}^{3}}d $ hybridization
[c] For $BF_{4}^{-},$
$H=\frac{1}{2}[3+4-0+1]=4,$
thus$s{{p}^{3}}$
hybridization [d] For $NH_{4}^{+},$
$H=\frac{1}{2}[5+4-1+0]=4,$
thus$s{{p}^{3}}$
hybridization Thus, only in $S{{F}_{4}},$
the central atom does not have $sp^3$ hybridization.