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Q. In which of the following graphs, the total change in momentum is zero?

Laws of Motion

Solution:

Total change in momentum $=\int F . d t=$ Area under $F t$ curve.
Area above $t$-axis will be positive and below $t$-axis will be negative in option (3)
Area $=-\left[\frac{1}{2} \times 5 \times 1\right]+\frac{1}{2} \times 5 \times 1=0$