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Q. In which of the following equilibrium $ {{K}_{c}} $ and $ {{K}_{p}} $ are not equal?

Jharkhand CECEJharkhand CECE 2013

Solution:

$ {{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}} $
$ \Delta {{n}_{g}}\ne 0 $
for the reaction
$ 2C(s)+{{O}_{2}}(g)2C{{O}_{2}} $
Thus, $ {{K}_{p}}\ne {{K}_{c}} $