Q. In which condition, the turgor pressure of the cell becomes equal to the osmotic pressure?
NTA AbhyasNTA Abhyas 2022
Solution:
1. Turgor pressure is the hydrostatic pressure that is generated in a cell when water enters the cell. The endosmosis process is responsible for the entry of water into the cell. The cytoplasm, upon receiving water from outside, swells and exerts pressure on the wall. Thus, this pressure is due to an increase in the turgidity of the cell. When a cell is fully turgid, the TP is maximum and not zero.
2. Wall pressure is a type of hydrostatic pressure that is present in a turgid cell to counter-balance the TP. This is equal in magnitude and opposite to TP. For a fully turgid cell, this is equal and opposite to TP. The cell can maintain its shape and size due to this WP.
3. The osmotic pressure is a measure of how much amount of water a cell can take up. For a fully turgid cell, OP is equal to TP.
4. The DPD of a fully turgid cell is zero This is because the OP is equal to TP. As $DPD=OP-TP$ , when the values of OP and TP are the same the DPD becomes 0. This also implies that the cell cannot take up more water and there is no DPD. DPD was previously called suction pressure.
2. Wall pressure is a type of hydrostatic pressure that is present in a turgid cell to counter-balance the TP. This is equal in magnitude and opposite to TP. For a fully turgid cell, this is equal and opposite to TP. The cell can maintain its shape and size due to this WP.
3. The osmotic pressure is a measure of how much amount of water a cell can take up. For a fully turgid cell, OP is equal to TP.
4. The DPD of a fully turgid cell is zero This is because the OP is equal to TP. As $DPD=OP-TP$ , when the values of OP and TP are the same the DPD becomes 0. This also implies that the cell cannot take up more water and there is no DPD. DPD was previously called suction pressure.