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  4. In which case depression freezing point is equal to cryoscopic constant for water:

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Q. In which case depression freezing point is equal to cryoscopic constant for water:

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Solution:

$\because \Delta T=K_{f} \times$ molality
59 g solution has 9 g glucose and 50 g water
$\therefore \Delta T=K_{f} \times\frac{9}{\frac{180\times50}{1000}}=K_{f}$