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Q.
In what manner will increase of pressure affect the following equation? $ C(s)+{{H}_{2}}O(g)CO(g)+{{H}_{2}}O(g) $
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Solution:
$ {{n}_{p}} $ (number of gaseous products)= 2 $ {{n}_{p}} $ (number of gaseous reactants) = 1 $ \because $ $ {{n}_{p}}>{{n}_{r}} $ Thus, according to Le-Chateliers principle, increase in pressure shifts the equilibrium towards left hand side (reactant side).