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Q. In water saturated air the mole fraction of water vapour is $0.02$. If the total pressure of the saturated air is $1.2\, atm$, the partial pressure of dry air is :

NEETNEET 2019Solutions

Solution:

$X_{H_2O} = 0.02$
$\therefore X_{gas} = 0.98$
$P_{total} =1.2 \,atm$
partial pressure of dry-air $= P_T \times $ mole fraction of dry-air
Partial pressure of dry-air $= 1.2\, atm \times 0.98$
$= 1 .176 \,atm$.