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Chemistry
In water saturated air the mole fraction of water vapour is 0.02. If the total pressure of the saturated air is 1.2 atm, the partial pressure of dry air is :
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Q. In water saturated air the mole fraction of water vapour is $0.02$. If the total pressure of the saturated air is $1.2\, atm$, the partial pressure of dry air is :
NEET
NEET 2019
Solutions
A
1.18 atm
20%
B
1.76 atm
22%
C
1.176 atm
41%
D
0.98 atm
16%
Solution:
$X_{H_2O} = 0.02$
$\therefore X_{gas} = 0.98$
$P_{total} =1.2 \,atm$
partial pressure of dry-air $= P_T \times $ mole fraction of dry-air
Partial pressure of dry-air $= 1.2\, atm \times 0.98$
$= 1 .176 \,atm$.