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  4. In triangle ABC, co-ordinates of A are (-1,3) and equations of medians and altitude through point B are 2 x+y=8 and 2 x+3 y=8 respectively, then

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Q. In triangle $ABC$, co-ordinates of $A$ are $(-1,3)$ and equations of medians and altitude through point $B$ are $2 x+y=8$ and $2 x+3 y=8$ respectively, then

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Solution:

$AC : 3x - 2y = k $
$- 3 - 6 = k$
$\therefore k=-9$
$3 x-2 y=-9 $
$M:(1,6) $
$\therefore C(3,9)$
$G(2,4) .$

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