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  4. In the wave equation y=0.5 sin (2 π/λ)(400 t-x) m the velocity of the wave will be :

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Q. In the wave equation
$y=0.5 \sin \frac{2 \pi}{\lambda}(400 t-x) m$
the velocity of the wave will be :

JEE MainJEE Main 2022Waves

Solution:

$ y =0.5 \sin \left(\frac{2 \pi}{\lambda} 400 t -\frac{2 \pi}{\lambda} x \right)$
$\omega=\frac{2 \pi}{\lambda} 400 $
$ K =\frac{2 \pi}{\lambda} $
$v =\frac{\omega}{ k } [ v =400 m / s ]$