In an isobaric process, $p=$ constant
Hence, $V \propto T$
i.e., $V=\left(\frac{n R}{p}\right) T$
$\therefore V-T$ graph is a straight line with slope $\propto \frac{1}{p}$
According to given figure, (slope) $_{2}>(\text { slope })_{1}$
$\therefore p_{2} < p_{1}$