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Q. In the table
Proton Electron Charge
23 X +3
46 43 Y

$X$ and $y$ are

Haryana PMTHaryana PMT 2007

Solution:

Atomic number $=$ number of protons
No. of electrons in positive ion $=$ no. of proton $-$ no. of $+v e$ charge on ion
No. of electrons in negative ion $=$ no. of- proton $+$ no. of $-v e$ charge on ion
(No. of electrons) $X=23-3=20$
(No. of charge) $Y=46-43=+3$