Q.
In the situation as shown in figure if acceleration of $B$ is a then find the acceleration of $A$ ($B$ always remains horizontal)
Laws of Motion
Solution:
Components of accelerations of $A$ and $B$ along normal $(\hat{n})$ to the incline of wedge should be same.
$\Rightarrow A \sin \theta=a \cos \left(2 \theta-90^{\circ}\right)$
$\Rightarrow A \sin \theta=a \sin 2 \theta$
$\Rightarrow A=2 a \cos \theta$