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Chemistry
In the Rosenmund's reaction RCOCl+H2 xrightarrowPd/BaSO4RCHO+HCl here BaSO4
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Q. In the Rosenmund's reaction $ RCOCl+{{H}_{2}}\xrightarrow{Pd/BaS{{O}_{4}}}RCHO+HCl $ here $ BaS{{O}_{4}} $
MGIMS Wardha
MGIMS Wardha 2009
A
promotes catalytic activity of $ Pd $
B
removes the $ HCl $ formed in the reaction
C
deactivates $ Pd $
D
activates $ Pd $
Solution:
$ BaS{{O}_{4}} $ decreases the activity of palladium