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Q. In the relation:
$y=a \sin (\omega t-k x)$
the dimensional formula for $\mathrm{k}$ is:

Physical World, Units and Measurements

Solution:

$\begin{aligned} &\text { Here; } \mathrm{kx} \text { is dimensionless. Hence, }\\ &[\mathrm{k}]=\left[\frac{2 \pi}{\lambda}\right]=\left[\mathrm{M}^{0} \mathrm{~L}^{-1} \mathrm{~T}^{0}\right] \end{aligned}$