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Q. In the refining of silver by electrolytic method, what will be the weight of 100 g Ag anode if 5A current is passed for hours? The purity of silver anode is 95% by weight.

MGIMS WardhaMGIMS Wardha 2013

Solution:

Only pure Ag from the anode is oxidised, which in turn is deposited at cathode. By Faradays first law, weight of Ag deposited at cathode, $ W=Zit $ $ =\frac{108\times 5\times 2\times 3600}{1\times 96500}=40.29\,g $ but anode is 95% pure w.r.t., Ag. Hence, actual loss is $ =40.29\times \frac{100}{95}=42.41\text{ }g $ Weight of Ag-anode after electrolysis $ =100-42.41=57.59\text{ }g $