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Chemistry
In the reduction of KMnO4 by warm acidified oxalic acid, the oxidation number of Mn changes from
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Q. In the reduction of $ KMnO_{4} $ by warm acidified oxalic acid, the oxidation number of $Mn$ changes from
BHU
BHU 2008
A
+ 4 to + 2
B
+ 6 to + 4
C
+ 7 to +2
D
+ 7 to + 4
Solution:
So, oxidation number of $Mn$ changes in the above reaction from $+7$ to $+2$.