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Q. In the reaction, $SO_{2}+2H_{2}S \rightarrow 3S+2H_{2}O$ , which choice has value twice that of equivalent mass of oxidising agent?

NTA AbhyasNTA Abhyas 2020Redox Reactions

Solution:

$\overset{+ 4}{S O_{2}}+2H_{2}S \rightarrow \overset{0}{3 S}+2H_{2}O$

Equivalent mass of $\text{SO}_{\text{2}} = \frac{\text{Molecular} \, \text{mass}}{\text{Change} \, \text{in} \, \text{oxidation} \, \text{number}}$

$=\frac{64}{4}=16 g$ .